0=4.905x^2-16x-13

Solution for 0=4.905x^2-16x-13 equation:

0=4.905x^2-16x-13

We move all terms to the left:

0-(4.905x^2-16x-13)=0

We add all the numbers together, and all the variables

-(4.905x^2-16x-13)=0

We get rid of parentheses

-4.905x^2+16x+13=0

a = -4.905; b = 16; c = +13;
Δ = b2-4ac
Δ = 162-4·(-4.905)·13
Δ = 511.06
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-\sqrt{511.06}}{2*-4.905}=\frac{-16-\sqrt{511.06}}{-9.81}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+\sqrt{511.06}}{2*-4.905}=\frac{-16+\sqrt{511.06}}{-9.81}
$